A sample of neon at 30.5 C exerts a pressure of 701 mm Hg. What is its density?

Answer 1

If you look at the ideal gas law, PV = nRT, we can use this to find the density of a gas. Here is how to go about this.

If you assume that you have 1 mole of neon (molar mass 20.18 g/mol) under the given conditions, then we can find the volume of neon gas: V = nRT/P = (1 mol)(62.36 Lmm/Kmol)(303.5K) / 701 mm = 26.999 L

Since we have 1 mol of neon occupying 26.999 L that's the same as 20.18 g /26.999 L = 0.747 g/L = density