Mark M. answered 11/25/19
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Retired Math prof with teaching and tutoring experience in trig.
2cotx / (1 + cot2x) = 2cotx / [1 + cos2x/sin2x]
= 2(cosx/sinx) / [(sin2x + cos2x) / sin2x]
= 2(cosx/sinx) / [1 / sin2x]
= 2(cosx/sinx)(sin2x / 1) = 2sinxcosx = sin(2x)