
Patrick B. answered 11/21/19
Math and computer tutor/teacher
sin^2 = (1 - cos2x)/2
cos^2 = (1 + cos2x)2
So then
sin^4 = (1-cos2x)^2/4
(1 - 2cos2x + cos^2(2x) ) / 4
(1 - 2 cos 2x + cos(4x)+1)/4
(2 - 2 cos2x + cos(4x))/4
Bern S.
asked 11/21/19Use the power-reducing formulas to rewrite the expression as an equivalent expression that does not contain powers of trigonometric functions greater than 1.
17sin4x
Patrick B. answered 11/21/19
Math and computer tutor/teacher
sin^2 = (1 - cos2x)/2
cos^2 = (1 + cos2x)2
So then
sin^4 = (1-cos2x)^2/4
(1 - 2cos2x + cos^2(2x) ) / 4
(1 - 2 cos 2x + cos(4x)+1)/4
(2 - 2 cos2x + cos(4x))/4
Denise G. answered 11/21/19
Algebra, College Algebra, Prealgebra, Precalculus, GED, ASVAB Tutor
17sin4x Reduce to sin2x
17(sin2x)(sin2x) Substitute in power reducing formula for sin2x
17[(1-cos 2x)/2][(1-cos 2x)/2]
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