What is the volume of 0.350 moles of an ideal gas at STP?

Question

What is the volume of 0.350 moles of an ideal gas at STP?

PV=nRT

Answer 1

You don't really need to use PV = nRT although you can. Here are TWO ways to solve this.

(1) At STP, 1 mole of an ideal gas = 22.4 liters

0.350 moles x 22.4 L/mole = 7.84 liters

(2) PV = nRT and at STP we set P = 1 atm and T = 273 degrees K

Solving for V:

V = nRT/P = (0.350 mol)(0.0821 Latm/Kmol)(273) / 1 atm = 7.84 liters