J.R. S. answered 11/20/19
Ph.D. University Professor with 10+ years Tutoring Experience
CO2(g) <==> CO2(aq)
∆Grxn = -386 kJ/mol - (-394.4 kJ/mol) = 8.4 kJ/mol
ln Keq = -∆G/RT = -8.4/(8.314)(298)
ln Keq = -0.00339
Keq = 0.9966 = Kp
Kp = PCO2(aq) / PCO2(g)
0.9966 = PCO2(aq) / 2.2 bar
PCO2(aq) = 2.2 bar