Akosua Y. answered 01/26/15
Tutor
5
(1)
Tutoring tailored to your way of learning
Hi Nathan,
To answer the question, I will label each of the equations
3x+2y=11 -----eqn 1
2x+6y=-2 ----- eqn 2
Now pick one of the equations and make one of the variables (x or y), the subject of the equation. So let's take equation 2 and make x the subject
2x+6y=-2 (subtract 6y from both sides of the equation so that 2x stands alone)
2x+6y-6y=-2-6y
2x=-2-6y (now divide both sides of the equation by 2 to make x the subject of the equation)
2x/2=-2/2 -6y/2
x=-1-3y (at this point we will substitute x=-1-3y into either eqn 1 or 2 in order to get a solution for y)
Substitute -1-3y for x in eqn 1
3(-1-3y) + 2y=11 (open the brackets)
-3 - 9y + 2y =11
-3 -7y =11 (by adding liked terms -9y+2y =-7y)
-3+3 -7y =11+3 (add 3 to each side of the equation)
-7y=14 (divide both sides of the equation by -7 to find solution for y)
-7y/-7 = 14/-7
y=-2
Now that we know y= -2, we can substitute it into eqn 2 to find x
2x+6y=-2 (substitute -2 for y)
2x+6(-2)=-2
2x-12=-2 (add 12 to both sides of the equation)
2x-12+12=-2+12
2x=10 (divide both sides of the equation by 2)
2x/2=10/2
x=5
So x=5 and y=-2. To prove our answer is right, we can substitute x for 5 and y for -2 in any of our eqn. Lets take eqn. 1
3x+2y=11
3(5)+2(-2)=11
15-4=11
11=11 (this statement is true, 11=11 and that's how we know x=5 and y=-2)
I hope this helps