J.R. S. answered 11/13/19
Ph.D. University Professor with 10+ years Tutoring Experience
B is not correct because in general, mass in not a determinant of boiling point, unless there are no other forces than dispersion. If dispersion forces were the only ones acting, then mass is important. In the case of F2 vs. HF we have F-F vs H-F
In F-F, this is a symmetrical molecule, with no dipole and no hydrogen bonding. So the only forces holding the F2 molecules together (intermolecular) would be dispersion.
With H-F however, there are strong hydrogen bonds among the HF molecules, in addition to dipoles and dispersion forces. Thus, HF will have a higher boiling point.
Alyssa P.
Ah okayy tysm!11/13/19