Alyssa P.

asked • 11/13/19

Help with IMFs plz

The electron cloud of HF is smaller than that of F2, however, HF has a much higher boiling point than F2 has. Which of the following explains how the dispersion-force model of intermolecular attraction does not account for the unusually high boiling point of HF?


a. F2 is soluble in water, whereas HF is insoluble in water.

b. The F2 molecule has a greater mass than the HF molecule has.

c. Liquid F2 has weak dispersion force attractions between its molecules, whereas liquid HF has strong ionic interactions between H+ and F- ions.

d. Liquid F2 has weak dispersion force attractions between its molecules, whereas liquid HF has both weak dispersion force attractions and hydrogen bonding interactions between its molecules.


I believe the answer is D, but can someone plz explain why B is not the answer? Thxx

2 Answers By Expert Tutors

By:

Alyssa P.

Ah okayy tysm!
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11/13/19

J.R. S.

tutor
Actually, I believe the correct answer would be (d). HF isn't really very ionic (like HCl), and it does have hydrogen bonding along with weak dispersion forces.
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11/13/19

J.R. S.

tutor
Just re-read the question and it asks which option does NOT account for the high boiling point of HF. Strange way to ask a question. In that case, a, b, and c do not account for the high boiling point.
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11/13/19

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