Themochem delta H

Question

The neutralization reaction between HCl and NaOH results in ∆Hº = -58 kJ·mol-1 HCl. What is the ∆H per mole of NaOH?

∆H = ? kJ·mol-1 NaOH

Answer 1

Looking at the balanced equation for the neutralization of HCl and NaOH...

HCl + NaOH ==> NaCl + H2O

Since the ∆H for 1 mole HCl = -58 kJ/mole, it will be the same for 1 mole of NaOH because in the balanced equation, 1 mole HCl = 1 mole NaOH.

Answer would be -58 kJ/mole NaOH.