P(-9,4) lies on the terminal arm of an angle in standard position...

Question

a) sketch the principal angle

b) what is the value of the related acute angle to the nearest degree?

c) what is the value of the principal angle to the nearest degree?

Answer 1

Since x>0 and y<0, the principal angle is in Quadrant IV:

360+tan^-1(-9/4)=360^o-66^o=294^o

66^o

294^o

Answer 2

Standard is in quad1. "P" is in quad2.