28C5 = 28! / [(5!)(28-5)!] = 28! / [(5!)(23!)]
Genesis P.
asked 11/11/19In how many ways can we select a committee of 5 people from a group of 28 candidates? Leave your answer in terms of factorials.
In how many ways can we select a committee of 5 people from a group of 28 candidates? Leave your answer in terms of factorials.
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