For the reaction below, Kc = 4.60 × 10⁻⁶. What is the equilibrium concentration of B if the reaction begins with 0.700 M A? A (g) ⇌ 3 B (g)

Answer 1

A <==> 3B

.7..........0.....Initial

-x.........+x....Change

0.7-x.....x.... Equilibrium

K = 4.6x10^-6 = [B]³[A] = (x³)(0.7-x)

solve for x and that will be your answer for the concentration of B