If Kp = 947 for the reaction below at 310 K, then what is the value of Kc? 2 A (g) + B (s) ⇌ 2 C (s) + D (g)

Answer 1

2A(g) + B(s) <==> 2C(s) + D(g)

Kc = Kp / (RT)^∆n

R = gas constant = 0.0821 Latm/Kmol

T = temperature = 310K

∆n = change in number of moles from reactant to product side = 1-2 = -1

Kc = 947 / (0.0821 • 310)^-1

Kc = 947 / 0.0393

Kc = 2.4x10⁴