Raegan G.

asked • 11/05/19

Write the equation of the line that is parallel to 3x=2-5y and passes through the point (3,-6)?

Nicholas O.

1. Start by rearranging 3x=2-5y into slope intercept form, y=mx+b. 1a. Add 5y to both sides, then minus 3x from both sides so it looks like 5y=-3x+2 1b. Divide both sides by 5 so you have y=-3/5x+2/5. 2. With this equation and your point given, use the point slope form, y-y1=m(x-x1) to solve. 2a. x1 in your point is 3 and y1 is -6. Use m from your rearranged equation, y=-3/5x+2/5 which is -3/5. 2b. Plug in numbers into point slope equation. It should be y+6=-3/5(x-3). 2c. Distributive property first on the right side so you have y+6=-3/5x+9/5. 2d. Minus 6 from both sides so you have y=-3/5x-21/5.
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11/07/19

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