i have an assignment due tonight for geometry. i really could use the help.

Question

write the equation of a line in slope intercept form that passes through (-2,5) and is parallel to y=3x-3.

Answer 1

The line parallel to this one will have the same slope. So m=3 Then you can use the following equation.

(y-y1)=m(x-x1) Plug in the values of (x1,y1) using the point provided. (-2,5)

(y-5)=3(x-(-2)) Simplify

(y-5)=3(x+2) Distribute

y-5=3x+6 Add 5 to both sides

y-5+5=3x+6+5 Simplify



y=3x+11

Answer 2

Hello Sami,

Two lines that are parallel have the same slope. When a line is written in slope-intercept form (y=mx+b), then m is the slope.

So, for this problem, y = 3x -3. A parallel line will take the form of y - 3x + b. So you need to find b.

But, we know that the the new line passes through (-2,5) So we plug x=-2 and y=5 into y=3x+b

and solve for b.

I get b = 11, so the answer is y= 3x +11