Chemistry Solubility Math Question 12

Question

K_sp for BaSO₄ is 1.07E-10. What is the molar solubility of BaSO₄?

Answer 1

BaSO₄(s) <==> Ba²⁺(aq) + SO₄^2-(aq)

Ksp = 1.07x10^-10 = [Ba²⁺][SO₄^2-]

1.07x10^-10 = [x][x] = x²

x = 1.03x10^-5 M = molar solubility of BaSO₄