If 131 g of hydrochloric acid reacts with 131 g of zinc, how many grams of zinc chloride are produced?

Answer 1

1. First balance the equation

2 HCl (g) + Zn (s) -> ZnCl₂ + H₂ (g)

1. Find the limiting reactant

131g HCl x 1 mole HCl = 3.51 mol HCl/ 2 mol HCl = 1.75

36.5 g HCl

131g Zn x 1 mole Zn = 2.00 mol Zn / 1 mol Zn = 2.00

65.38 g Zn

The limiting reactant is HCl

1. Use the LR to calculate amount of product

131g HCl x 1 mole HCl x 1 mol ZnCl₂ x 136.38 g ZnCl₂ ~ 246 g ZnCl₂

36.5 g HCl 2 mol HCl 1 mol ZnCl₂