J.R. S. answered 11/03/19
Ph.D. University Professor with 10+ years Tutoring Experience
HAc + OH- === > Ac- + H2O
o.28...0.18..............0..........Initual
-0.18...-0.18..........+0.18.....Change
0.10......0...............0.28.....Equilibrium
pK = pKa + log [Ac] /[HAc]
pH =4.75 + log (0.28/0.20)
pH = 4.75 + 0.45 = 5.2