Find the equation of a line tangent to the circle x^2+y^2=8 at the point (–2, 2).

Answer 1

The tangent line is perpendicular to the radius of the circle from (0, 0) to (-2, 2).

The slope of the radius is -1. The slope of the tangent line is 1

Using point-slope form

(y - 2) = (x + 2)