5x + 3y = 15
3y = -5x + 15
y = (-5/3)x + 5
We have two options for solving.
y - 1 = (3/5)(x - 5)
y - 1 = (3/5)x - 3
y = (3/5)x - 2
orrrr...
1 = (3/5)(5) + b
1 = 3 + b
b = -2
y = (3/5)x - 2
Cedes N.
asked 11/01/19Write an equation of the line passing through the point (5,1) that is perpendicular to the line 5x+3y=15
5x + 3y = 15
3y = -5x + 15
y = (-5/3)x + 5
We have two options for solving.
y - 1 = (3/5)(x - 5)
y - 1 = (3/5)x - 3
y = (3/5)x - 2
orrrr...
1 = (3/5)(5) + b
1 = 3 + b
b = -2
y = (3/5)x - 2
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