Angle EAB and angle ABC are right angles.

Question

AB = 4, BC = 6, AE = 8, and line segment AC and line segment BE intersect at point D. What is the difference between the ares of triangle ADE and triangle BDC?

here is the link to the figure, please remove the spaces

https: //docs. google .com /document / d / 1oX0zrFByTmHw9VUd0fOEWwXJKki6BLgYSDYuU9pvwbY/ edit?usp=sharing

Answer 1

Begin by finding the area of ΔABE and ΔABC (area of triangle = (base * height)/2)

ΔABE = (4 * 8)/2 = 32/2 = 16

ΔABC = (4 * 6)/2 = 24/2 = 12

Since ΔABD is part of both triangles, you can subtract ΔABC from ΔABE to find the difference between ΔADE and ΔBDC.

ΔABE - ΔABD = 16 - 12 = 4