J.R. S. answered 10/29/19
Ph.D. University Professor with 10+ years Tutoring Experience
The first reaction is the formation of the precipitate of lead hydroxide.
2NaOH(aq) + Pb(NO3)2(aq) ==> Pb(OH)2(s) + 2NaNO3(aq)
The next reaction is that of the precipitate reacting with excess base to produce the soluble lead complex
Pb(OH)2(s) + 2OH-(aq) ==> Pb(OH)42-(aq)