Buffer Solution Chemistry Math Question 9

Question

When 20 mL of 0.26 M sulfuric acid is titrated with a standard solution of 0.287 M NaOH solution, what volume of base is required to reach the second equivalence point of the titration?

Answer 1

H2SO4 + 2NaOH ==> Na2SO4 + 2H2O

moles H2SO4 present = 0.020 L x 0.26 mol/L = 0.0052 moles

moles NaOH needed for complete neutralization (to 2nd equivalence) = 0.0052 mol H2SO4 x 2 mol NaOH/mole H2SO4 = 0.0104 moles NaOH needed

Volume of NaOH needed: (x L)(0.287 mol/L) = 0.0104 moles

x = 0.0362 L

x = 36.2 mls = 36 mls NaOH needed (to 2 significant figures)