J.R. S. answered 10/29/19
Ph.D. University Professor with 10+ years Tutoring Experience
This is analogous to your previous question (#6) where you will use the HH equation, solve for log (salt/acid) and then find moles of salt, and finally convert to grams of salt.
pH = pKa + log [salt]/[acid]
pH = 3.5
pKa = 3.337
[acid] = 0.3 M
3.5 = 3.337 + log (x/0.3)
Solve for x which will give you M (molarity) of sodium nitrate needed. Use the volume of 300 ml (0.300 L) to convert that to moles needed and finally, multiply that by the molar mass of sodium nitrate to obtain grams needed.
Again, refer to your previous question #6 which is solved in an identical manner as this problem.