The equation e^y+y(x-2)=x^2-8 implicitly defines y as a function of x near the point (3,0). Using linearization to estimate the value of y when x=2.8 one gets:

Question

The equation e^y+y(x-2)=x²-8 implicitly defines y as a function of x near the point (3,0). Using linearization to estimate the value of y when x=2.8 one gets:

a. -0.8

b. -0.6

c. -0.4

d. 0.4

e. 0.6

f. none of the above

Answer 1