How many grams of sodium hydroxide are present in 252.0 mL of a 0.300 M NaOH solution?

Answer 1

0.300 M NaOH = 0.300 moles NaOH/L

252.0 ml = 0.2520 L

moles NaOH = 0.2520 L x 0.300 moles/L = 0.0756 moles NaOH

MASS = 0.0756 moles NaOH X 39.99g/mol = 3.02 g NaOH