The activation energy, Ea, for a particular reaction is 13.6 kJ/mol. If the rate constant at 754 °C is 24.5/min, at what temperature (in °C) will the rate constant be 10.7/min? (R = 8.314 J/mol • K)

Answer 1

Ea = 13,600 J/mol

k1 = 24.5

k2 = 10.7

T1 = 754 + 273 = 1027K

T2 = ?

Use the Arrhenius equation, plug in the values and solve for T2 an then subtract 273 to get ºC

ln (k1/k2) = Ea/R (1/T2 - 1/T1)