What is the solubility in moles/liter for calcium sulfate at 25 oC given a Ksp value of 2.4 x 10-5.

Question

What is the solubility in moles/liter for calcium sulfate at 25 ^oC given a K_sp value of 2.4 x 10^-5.

The answer is: 4.9e-3

please explain and show your steps

Answer 1

CaSO₄(s) <===> Ca²⁺ + SO₄^2-

Ksp = [Ca²⁺][SO₄^2-]

2.4x10^-5 = (x)(x)

x² = 2.4x10^-5

x = 4.9x10^-3 M