The Ksp of Al(OH)3 at 25 oC is 1 x 10-33. Consider a solution that is 1.0 x 10-10 M in Al(NO3)3 and 1.0 x 10-8 M in NaOH.

Question

The K_sp of Al(OH)₃ at 25 ^oC is 1 x 10^-33. Consider a solution that is 1.0 x 10^-10 M

in Al(NO₃)₃ and 1.0 x 10^-8 M in NaOH.

the answer is: Q < K_sp and a precipitate will not form

please explain

Answer 1

Al(OH)₃(s) <===> Al³⁺ + 3OH^-

Ksp = [Al³⁺][OH^-]³

Q = [Al³⁺][OH^-]³

[Al³⁺] = 1.0x10^-10 M from the Al(NO3)3

[OH-] = 1.0x10^-8 M from the NaOH

Q = (1.0x10^-10)(1.0x10^-8)³

Q = 1.0x10^-34

1.0x10^-34 (Q) is LESS THAN 1.0x10^-33 (Ksp). A precipitate will not form.