At 25 oC the solubility of copper(II) iodate is 3.27 x 10-3 mol/L. Calculate the value of Ksp at this temperature.

Question

At 25 ^oC the solubility of copper(II) iodate is 3.27 x 10^-3 mol/L. Calculate the value of K_sp at this temperature.

The answer is 1.4e-7

please show you steps

Answer 1

Cu(IO₃)₂(s) <===> Cu²⁺ + 2IO₃^-

Ksp = [Cu²⁺][IO₃^-]²

[Cu²⁺] = 3.27x10^-3

[IO₃^-] = 2 x 3.27x10^-3 = 6.54x10^-3

Ksp = (3.27x10^-3)(6.54x10^-3)²

Ksp = 1.39x10^-7 = 1.4x10^-7