What pressure would it take to compress 350. L of helium gas initially at 1.00 atm into a 2.00 L tank at constant temperature?

Answer 1

Look at what you are given:

An initial volume (V1) = 350. L

An initial pressure (P1) = 1.00 atm

A final volume (V2) = 2.00 L

What are you asked to find?

Find the final pressure (P2) = ?

NOTE: the temperature is constant, so it does not enter the calculations.

At constant temperature you are dealing with Boyles Law: P1V1 = P2V2

Plugging in the values, we have (1.00 atm)(350. L) = (P2)(2.00 L) and solving for P2 we have...

P2 = (1)(350)/(2) = 175 atm