J.R. S. answered 10/20/19
Ph.D. University Professor with 10+ years Tutoring Experience
At STP (standard temperature and pressure) the molar volume of an ideal gas is 22.4 liters/mole. Using this information, it is easy to then find the volume (in liters) occupied by 60.0 g of Ar gas.
60.0 g Ar x 1 mol Ar/39.95 g = 1.5019 moles Ar
1.5019 moles Ar x 22.4 liters/mole = 33.6 liters (to 3 significant figures)