J.R. S. answered 10/19/19
Ph.D. University Professor with 10+ years Tutoring Experience
Since you will be using the vapor pressure of water at the "temperature" where the gas is collected, the pressure you will use will be lower than the actual pressure (pressure at 25º is less than that at 35º). This value will be subtracted from measured pressure of the collected gas resulting is a pressure of collected gas that is greater than actual. From PV = nRT you will be solving for n, but the pressure (P) you use will be too high, so moles calculated will be too high. Since molar mass = mass/moles, the calculated molar mass will be too low.