How much 0.1M NaOH will you need to titrate 5mL of 1M CH3COOH?

Answer 1

NaOH + CH₃COOH ==> CH₃COONa + H2O

Moles CH₃COOH present = 0.005 L x 1 mol/L = 0.005 moles

moles NaOH needed = 0.005 mol CH3COOH x 1 mol NaOH/mole CH₃COOH = 0.005 mol NaOH needed

Volume NaOH: x L * 0.1 mol/L = 0.005 moles

x = 0.05 L = 50 ml