William W. answered 10/18/19
Experienced Tutor and Retired Engineer
If sin2(θ) + cos2(θ) = 1 then sin2(θ) = 1 - cos2(θ)
Substitute "1 - cos2(θ)" for "sin2(θ)" in cos(2θ) = cos2(θ) - sin2(θ) to get:
cos(2θ) = cos2(θ) - (1 - cos2(θ)) = 2cos2(θ) - 1
Bobby L.
asked 10/18/19This was the first question: Let α=β=θ in the formula cos(α+β) and thus derive a formula for cos2θ
And I solved it as: cosθcosθ - sinθsinθ = cos2 - sin2
Now, the question I can't figure out is: Use the identity sin2 θ + cos2θ = 1 in order to write the above answer in terms of cosine only.
If anyone could help me out with that, I would be very thankful. Again, this is just the practice exam. The real exam is tomorrow.
William W. answered 10/18/19
Experienced Tutor and Retired Engineer
If sin2(θ) + cos2(θ) = 1 then sin2(θ) = 1 - cos2(θ)
Substitute "1 - cos2(θ)" for "sin2(θ)" in cos(2θ) = cos2(θ) - sin2(θ) to get:
cos(2θ) = cos2(θ) - (1 - cos2(θ)) = 2cos2(θ) - 1
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