J.R. S. answered 10/17/19
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NaOH + HBr ==> NaBr + H2O
moles HBr used = 0.0343 L x 0.200 mol/L = 0.00686 moles
moles NaOH = 0.00686 b/c it’s a 1:1 mol ratio with HBr
Concentration of NaOH = 0.00686 mol/0.020 L = 0.343 M