What volume (in L) of 1.1 M FeCl₃ would be required to obtain 0.57 moles of Cl⁻ ions?

Answer 1

1.1 mol/L FeCl_{3 x} 3 mol Cl^-/mol FeCl₃ = 3.3 mol Cl^-/L

(x L)(3.3 mol Cl^-/L) = 0.57 moles Cl^-

x = 0.17 L