Hunter L. answered • 10/16/19

Experienced and Patient UCLA Math and Science Tutor

The mean of this approximate normal distribution is (22%) * (164 people) = 36.08 people

The standard deviation is √(n*p*q) = √(164 * 22% * 78%) = 5.31 people

using normcdf(-999999, 42, 36.08, 5.31) on a TI-84 or TI-83, we get an answer of 86.75%