Hunter L. answered 10/16/19
Experienced and Patient UCLA Math and Science Tutor
The mean of this approximate normal distribution is (22%) * (164 people) = 36.08 people
The standard deviation is √(n*p*q) = √(164 * 22% * 78%) = 5.31 people
using normcdf(-999999, 42, 36.08, 5.31) on a TI-84 or TI-83, we get an answer of 86.75%