Limiting Reactant: Compare Products

Question

For the following reaction, 0.241 moles of barium hydroxide are mixed with 0.416 moles of sulfuric acid.

barium hydroxide (aq)+sulfuric acid (aq)= barium sulfate (s)+ water(l)

What is the formula for the limiting reagent?

What is the maximum amount of barium sulfate that can be produced?

__________ moles

Answer 1

Ba(OH)₂(aq) + H₂SO₄(aq) ==> BaSO₄(s) + 2H₂O(l) ... balanced equation

Since Ba(OH)₂ and H₂SO₄ react in a 1:1 mole ratio, the limiting reacting would be Ba(OH)₂

Maximum amount of BaSO₄ than can be produced is 0.241 moles because it, too is in a 1:1 mole ratio to the limiting reactant barium hydroxide.