J.R. S. answered 10/15/19
Ph.D. University Professor with 10+ years Tutoring Experience
2Na(s) + 2H2O(l) ==> 2NaOH(aq) + H2(g) ... balanced equation
Assuming H2(g) behaves as an ideal gas, we can use the ideal gas law equation to find moles (n) of H2(g)
PV = nRT
n = PV/RT = (1 atm)(10.5 L)/(0.0821 Latm/Kmol)(298K)
n = 0.429 moles H2
Now, from the balanced equation, we can find the moles and mass of Na needed to produce 0.429 moles H2:
0.429 mol H2 x 2 mol Na/mol H2 x 22.99 g/mol = 19.7 g of Na needed