J.R. S. answered 10/15/19
Ph.D. University Professor with 10+ years Tutoring Experience
Temperature and Pressure are constant, so moles (n) and volume (V) change.
V1/n1 = V2/n2
n1 = 0.1500 moles + 0.1875 moles = 0.3375 moles
V1 = 10.9 L
n2 = 0.3375 moles x 10/9 = 0.375 (there are 10 moles of gas on product side and 9 moles on reactant side)
V2 = ?
10.9/0.3375 = V2/0.375
V2 = 12.1 L
V1/n1 = V2/n2
V1 = 8.80 L
n1 = 0.1200 + 0.100 = 0.2400
V2 = ?
n2 = 0.2400 x 1/2 = 0.1200 (there is 1 mole of gas on product side and 2 moles on reactant side)
8.80/0.2400 = V2/0.1200
solve for V2