oxidation elements and reducing agents

Question

Pb + ClO4-+ 2H+ClO3- + Pb2++ H2O

Name of element oxidized:

Formula of oxidizing reagent:

Name of element reduced:

Formula of reducing agent:

Zn(OH)42- + Mn(OH)2Zn + MnO2+ 2H2O+ 2OH-

Name of element oxidized:

Formula of oxidizing reagent:

Name of element reduced:

Formula of reducing agent:

Answer 1

Pb + ClO₄^-+ 2H⁺ClO₃^- + Pb²⁺+ H₂O

Pb goes from ox. no. zero to ox. no. 2+. Pb lost 2 electrons. Pb has been oxidized.

ClO₄^- is the oxidizing agent

Cl in ClO₄^- goes from ox. no. 7+ to ox. no. 5+. Cl gained 2 electrons. Cl has been reduced

Pb is the reducing agent

Zn(OH)₄^2- + Mn(OH)₂Zn + MnO₂+ 2H₂O+ 2OH^-

Mn in Mn(OH)₂ goes from ox. no. 2+ to ox. no. 4+ in MnO₂. Mn has lost 2 electrons. Mn has been oxidized

Zn(OH)₄^2- is the oxidizing agent

Zn in Zn(OH)₄^2- goes from ox. no. 2+ to ox. no. zero. Zn has gained 2 electrons. Zn has been reduced

Mn(OH)₂ is the reducing agent