A reaction was shown to follow second-order kinetics. How much time is required for [A] to change from 0.500 M to 0.250 M? (k = 0.456 M⁻¹ s⁻¹)

Answer 1

The integrated rate law for 2nd order is 1/[A] = 1/[A]_o + kt

1/0.250 = 1/0.500 + 0.456t

4 = 2 + 0.456t

t = 4.39 sec