J.R. S. answered 10/14/19
Ph.D. University Professor with 10+ years Tutoring Experience
14 N atoms x 14.01 amu/atom = 196.14 amu/molecule
196.14 g/x g = 14.47%/100%
14.47x = 19614
x = 19614/14.47 = 1355 g/mole = molar mass
Vanessa C.
asked 10/14/19Vitamin B12, cyanocobalamin, is essential for human nutrition. It is concentrated in animal tissue but not in higher plants. Although nutritional requirements for the vitamin are quite low, people who abstain completely from animal products may develop a deficiency anemia. Cyanocobalamin is the form used in vitamin supplements. It contains 14.47% nitrogen by mass. Calculate the molar mass of cyanocobalamin, assuming that there are fourteen atoms of nitrogen in every molecule of cyanocobalamin.
answer in g/mol format
J.R. S. answered 10/14/19
Ph.D. University Professor with 10+ years Tutoring Experience
14 N atoms x 14.01 amu/atom = 196.14 amu/molecule
196.14 g/x g = 14.47%/100%
14.47x = 19614
x = 19614/14.47 = 1355 g/mole = molar mass
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