J.R. S. answered 10/14/19
Ph.D. University Professor with 10+ years Tutoring Experience
You didn't provide any state conditions, such as is the NaCl solid or aqueous. If aqueous, then there is no reaction since you will have only ions in solution without a gas or precipitate being formed. If it is a solid, you still won't form Na2SO4 as the reaction, at room temperature would be NaCl(s) + H2SO4(aq) --> NaHSO4(s) + HCl(g). Having said all of this, if we assume that the question is posed to see if you can balance and use stoichiometry, then we will write the following:
H2SO4 + 2NaCl ==> Na2SO4 + 2HCl
0.500 moles NaCl x 1 mole Na2SO4/2 moles NaCl x 142 g Na2SO4/mole = 35.5 g Na2SO4 formed (assuming H2SO4 is present in excess)