How many grams of NH3 can be produced from 4.77 mol of N2 and excess H2. Express your answer numerically in grams.

Question

To understand how to use stoichiometry to convert between quantities of reactants and products in chemical equations.

Answer 1

First, you must write the correctly balanced equation:

N₂ + 3H₂ ==> 2NH₃

Next, since H₂ is in excess, the amount of product (NH3) will depend only on amount of N₂ present.

From the balanced equation, it can be seen that ONE mole N₂ produces TWO moles NH₃. Thus, you can set up a simple proportion or use dimensional analysis to find moles of NH₃ produced from 4.77 moles N₂.

4.77 moles N₂ x 2 moles NH₃/1 mole N₂ = 9.54 moles NH₃ produced.

Simply convert this to grams:

9.54 moles NH₃ x 17 g/mole = 162 g NH₃ produced