The pressure should be P = 65cos(4*pi*t - pi) + 145
(I understand from the description that the period is 1/2 hour)
Teresa M.
asked 10/08/19The pressure (in pounds per square foot), in a pipe varies over time. Two times an hour, the pressure oscillates from a low of 80 to a high of 210 and then back to a low of 80. The pressure at time t=0 is 80.
The pressure should be P = 65cos(4*pi*t - pi) + 145
(I understand from the description that the period is 1/2 hour)
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