Neutralization Reaction

Question

Write the balanced neutralization reaction that occurs between H2SO4 and KOH in aqueous solution. Phases are optional. neutralization reaction:

Suppose 0.750 L of 0.480 M H2SO4 is mixed with 0.700 L of 0.200 M KOH . What concentration of sulfuric acid remains after neutralization?

Answer 1

Balanced equation:

H₂SO₄(aq) + 2KOH(aq) ==> K₂SO₄(aq0 + 2H₂O(l)

moles H₂SO₄ initially present = 0.750 L x 0.480 mol/L = 0.360 moles

moles KOH initially present = 0.700 L x 0.200 mol/L = 0.140 moles

moles H₂SO₄ neutralized by 0.140 moles KOH = 0.140 mol KOH x 1 mol H₂SO₄/2 mol KOH = 0.070 moles

moles H₂SO₄ left over = 0.360 - 0.070 = 0.290 moles H₂SO₄

Final volume = 0.750 L + 0.700 L = 1.45 L

Final concentration of H2SO4 = 0.290 moles/1.45 L = 0.200 M H₂SO₄