An aqueous solution of iron(II) sulfate (FeSO4) is prepared by dissolving 2.75 g in sufficient deionized water to form a 150.00 mL solution. Calculate the molarity of the solution.

Answer 1

Molar mass FeSO₄ = 152 g/mol

2.75 g x 1 mol/152 g = 0.0181 moles

molarity = moles/liter

moles = 0.0181

liters = 150 ml x 1 L /1000 ml = 0.15 L

Molarity = 0.0181 mol/0.15 L = 0.121 M (3 sig figs)