Where is the midpoint of XY if the endpoints are X(4x, 2y) and Y(0, -2y)?

Answer 1

Similar to the other one.

X(4x,2y)

Y(0,-2y)

what's (4x-0)/2?

and (2y-(-2y))/2?

That's your midpoint.

Half the line at an angle is merely half the height and half the length.

Answer 2

(4x+0)/2 = 2x

(2y+2y)/2= 2y

midpoint (2x,2y)