J.R. S. answered 10/01/19
Ph.D. University Professor with 10+ years Tutoring Experience
2KOH + CO2 ==> K2CO3 + H2O ... balanced equation
moles CO2 present = 27.9 g x 1 mol/44 g = 0.634 moles
mass KOH needed = 0.634 mol CO2 x 2 mol KOH/mol CO2 x 56.11g/mol = 71.1 g